Optimal. Leaf size=214 \[ -\frac{2 b^3 (d+e x)^{3/2} (-4 a B e-A b e+5 b B d)}{3 e^6}+\frac{4 b^2 \sqrt{d+e x} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{e^6}+\frac{4 b (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{e^6 \sqrt{d+e x}}-\frac{2 (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{3 e^6 (d+e x)^{3/2}}+\frac{2 (b d-a e)^4 (B d-A e)}{5 e^6 (d+e x)^{5/2}}+\frac{2 b^4 B (d+e x)^{5/2}}{5 e^6} \]
[Out]
_______________________________________________________________________________________
Rubi [A] time = 0.289292, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.061 \[ -\frac{2 b^3 (d+e x)^{3/2} (-4 a B e-A b e+5 b B d)}{3 e^6}+\frac{4 b^2 \sqrt{d+e x} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{e^6}+\frac{4 b (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{e^6 \sqrt{d+e x}}-\frac{2 (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{3 e^6 (d+e x)^{3/2}}+\frac{2 (b d-a e)^4 (B d-A e)}{5 e^6 (d+e x)^{5/2}}+\frac{2 b^4 B (d+e x)^{5/2}}{5 e^6} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^2)/(d + e*x)^(7/2),x]
[Out]
_______________________________________________________________________________________
Rubi in Sympy [A] time = 100.63, size = 218, normalized size = 1.02 \[ \frac{2 B b^{4} \left (d + e x\right )^{\frac{5}{2}}}{5 e^{6}} + \frac{2 b^{3} \left (d + e x\right )^{\frac{3}{2}} \left (A b e + 4 B a e - 5 B b d\right )}{3 e^{6}} + \frac{4 b^{2} \sqrt{d + e x} \left (a e - b d\right ) \left (2 A b e + 3 B a e - 5 B b d\right )}{e^{6}} - \frac{4 b \left (a e - b d\right )^{2} \left (3 A b e + 2 B a e - 5 B b d\right )}{e^{6} \sqrt{d + e x}} - \frac{2 \left (a e - b d\right )^{3} \left (4 A b e + B a e - 5 B b d\right )}{3 e^{6} \left (d + e x\right )^{\frac{3}{2}}} - \frac{2 \left (A e - B d\right ) \left (a e - b d\right )^{4}}{5 e^{6} \left (d + e x\right )^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**2/(e*x+d)**(7/2),x)
[Out]
_______________________________________________________________________________________
Mathematica [A] time = 0.438177, size = 337, normalized size = 1.57 \[ -\frac{2 \left (a^4 e^4 (3 A e+2 B d+5 B e x)+4 a^3 b e^3 \left (A e (2 d+5 e x)+B \left (8 d^2+20 d e x+15 e^2 x^2\right )\right )-6 a^2 b^2 e^2 \left (3 B \left (16 d^3+40 d^2 e x+30 d e^2 x^2+5 e^3 x^3\right )-A e \left (8 d^2+20 d e x+15 e^2 x^2\right )\right )+4 a b^3 e \left (B \left (128 d^4+320 d^3 e x+240 d^2 e^2 x^2+40 d e^3 x^3-5 e^4 x^4\right )-3 A e \left (16 d^3+40 d^2 e x+30 d e^2 x^2+5 e^3 x^3\right )\right )+b^4 \left (A e \left (128 d^4+320 d^3 e x+240 d^2 e^2 x^2+40 d e^3 x^3-5 e^4 x^4\right )-B \left (256 d^5+640 d^4 e x+480 d^3 e^2 x^2+80 d^2 e^3 x^3-10 d e^4 x^4+3 e^5 x^5\right )\right )\right )}{15 e^6 (d+e x)^{5/2}} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^2)/(d + e*x)^(7/2),x]
[Out]
_______________________________________________________________________________________
Maple [B] time = 0.013, size = 469, normalized size = 2.2 \[ -{\frac{-6\,{b}^{4}B{x}^{5}{e}^{5}-10\,A{b}^{4}{e}^{5}{x}^{4}-40\,Ba{b}^{3}{e}^{5}{x}^{4}+20\,B{b}^{4}d{e}^{4}{x}^{4}-120\,Aa{b}^{3}{e}^{5}{x}^{3}+80\,A{b}^{4}d{e}^{4}{x}^{3}-180\,B{a}^{2}{b}^{2}{e}^{5}{x}^{3}+320\,Ba{b}^{3}d{e}^{4}{x}^{3}-160\,B{b}^{4}{d}^{2}{e}^{3}{x}^{3}+180\,A{a}^{2}{b}^{2}{e}^{5}{x}^{2}-720\,Aa{b}^{3}d{e}^{4}{x}^{2}+480\,A{b}^{4}{d}^{2}{e}^{3}{x}^{2}+120\,B{a}^{3}b{e}^{5}{x}^{2}-1080\,B{a}^{2}{b}^{2}d{e}^{4}{x}^{2}+1920\,Ba{b}^{3}{d}^{2}{e}^{3}{x}^{2}-960\,B{b}^{4}{d}^{3}{e}^{2}{x}^{2}+40\,A{a}^{3}b{e}^{5}x+240\,A{a}^{2}{b}^{2}d{e}^{4}x-960\,Aa{b}^{3}{d}^{2}{e}^{3}x+640\,A{b}^{4}{d}^{3}{e}^{2}x+10\,B{a}^{4}{e}^{5}x+160\,B{a}^{3}bd{e}^{4}x-1440\,B{a}^{2}{b}^{2}{d}^{2}{e}^{3}x+2560\,Ba{b}^{3}{d}^{3}{e}^{2}x-1280\,B{b}^{4}{d}^{4}ex+6\,A{a}^{4}{e}^{5}+16\,Ad{a}^{3}b{e}^{4}+96\,A{a}^{2}{b}^{2}{d}^{2}{e}^{3}-384\,Aa{b}^{3}{d}^{3}{e}^{2}+256\,A{d}^{4}{b}^{4}e+4\,B{a}^{4}d{e}^{4}+64\,B{a}^{3}b{d}^{2}{e}^{3}-576\,B{d}^{3}{a}^{2}{b}^{2}{e}^{2}+1024\,B{d}^{4}a{b}^{3}e-512\,{b}^{4}B{d}^{5}}{15\,{e}^{6}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^(7/2),x)
[Out]
_______________________________________________________________________________________
Maxima [A] time = 0.729691, size = 562, normalized size = 2.63 \[ \frac{2 \,{\left (\frac{3 \,{\left (e x + d\right )}^{\frac{5}{2}} B b^{4} - 5 \,{\left (5 \, B b^{4} d -{\left (4 \, B a b^{3} + A b^{4}\right )} e\right )}{\left (e x + d\right )}^{\frac{3}{2}} + 30 \,{\left (5 \, B b^{4} d^{2} - 2 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d e +{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{2}\right )} \sqrt{e x + d}}{e^{5}} + \frac{3 \, B b^{4} d^{5} - 3 \, A a^{4} e^{5} - 3 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 6 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 6 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} + 3 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4} + 30 \,{\left (5 \, B b^{4} d^{3} - 3 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e + 3 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{2} -{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{3}\right )}{\left (e x + d\right )}^{2} - 5 \,{\left (5 \, B b^{4} d^{4} - 4 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e + 6 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{2} - 4 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{3} +{\left (B a^{4} + 4 \, A a^{3} b\right )} e^{4}\right )}{\left (e x + d\right )}}{{\left (e x + d\right )}^{\frac{5}{2}} e^{5}}\right )}}{15 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(7/2),x, algorithm="maxima")
[Out]
_______________________________________________________________________________________
Fricas [A] time = 0.287915, size = 581, normalized size = 2.71 \[ \frac{2 \,{\left (3 \, B b^{4} e^{5} x^{5} + 256 \, B b^{4} d^{5} - 3 \, A a^{4} e^{5} - 128 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 96 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 16 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} - 2 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4} - 5 \,{\left (2 \, B b^{4} d e^{4} -{\left (4 \, B a b^{3} + A b^{4}\right )} e^{5}\right )} x^{4} + 10 \,{\left (8 \, B b^{4} d^{2} e^{3} - 4 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d e^{4} + 3 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{5}\right )} x^{3} + 30 \,{\left (16 \, B b^{4} d^{3} e^{2} - 8 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e^{3} + 6 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{4} -{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{5}\right )} x^{2} + 5 \,{\left (128 \, B b^{4} d^{4} e - 64 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e^{2} + 48 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{3} - 8 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{4} -{\left (B a^{4} + 4 \, A a^{3} b\right )} e^{5}\right )} x\right )}}{15 \,{\left (e^{8} x^{2} + 2 \, d e^{7} x + d^{2} e^{6}\right )} \sqrt{e x + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(7/2),x, algorithm="fricas")
[Out]
_______________________________________________________________________________________
Sympy [A] time = 15.6886, size = 2440, normalized size = 11.4 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**2/(e*x+d)**(7/2),x)
[Out]
_______________________________________________________________________________________
GIAC/XCAS [A] time = 0.297136, size = 765, normalized size = 3.57 \[ \frac{2}{15} \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} B b^{4} e^{24} - 25 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{4} d e^{24} + 150 \, \sqrt{x e + d} B b^{4} d^{2} e^{24} + 20 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{3} e^{25} + 5 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{4} e^{25} - 240 \, \sqrt{x e + d} B a b^{3} d e^{25} - 60 \, \sqrt{x e + d} A b^{4} d e^{25} + 90 \, \sqrt{x e + d} B a^{2} b^{2} e^{26} + 60 \, \sqrt{x e + d} A a b^{3} e^{26}\right )} e^{\left (-30\right )} + \frac{2 \,{\left (150 \,{\left (x e + d\right )}^{2} B b^{4} d^{3} - 25 \,{\left (x e + d\right )} B b^{4} d^{4} + 3 \, B b^{4} d^{5} - 360 \,{\left (x e + d\right )}^{2} B a b^{3} d^{2} e - 90 \,{\left (x e + d\right )}^{2} A b^{4} d^{2} e + 80 \,{\left (x e + d\right )} B a b^{3} d^{3} e + 20 \,{\left (x e + d\right )} A b^{4} d^{3} e - 12 \, B a b^{3} d^{4} e - 3 \, A b^{4} d^{4} e + 270 \,{\left (x e + d\right )}^{2} B a^{2} b^{2} d e^{2} + 180 \,{\left (x e + d\right )}^{2} A a b^{3} d e^{2} - 90 \,{\left (x e + d\right )} B a^{2} b^{2} d^{2} e^{2} - 60 \,{\left (x e + d\right )} A a b^{3} d^{2} e^{2} + 18 \, B a^{2} b^{2} d^{3} e^{2} + 12 \, A a b^{3} d^{3} e^{2} - 60 \,{\left (x e + d\right )}^{2} B a^{3} b e^{3} - 90 \,{\left (x e + d\right )}^{2} A a^{2} b^{2} e^{3} + 40 \,{\left (x e + d\right )} B a^{3} b d e^{3} + 60 \,{\left (x e + d\right )} A a^{2} b^{2} d e^{3} - 12 \, B a^{3} b d^{2} e^{3} - 18 \, A a^{2} b^{2} d^{2} e^{3} - 5 \,{\left (x e + d\right )} B a^{4} e^{4} - 20 \,{\left (x e + d\right )} A a^{3} b e^{4} + 3 \, B a^{4} d e^{4} + 12 \, A a^{3} b d e^{4} - 3 \, A a^{4} e^{5}\right )} e^{\left (-6\right )}}{15 \,{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(7/2),x, algorithm="giac")
[Out]